By Goldberg, David Elliott
Contains 673 totally solved difficulties and examples with factors of chemistry concepts.
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Ans. 1 What is wrong with the following problem? Change 125 g to milliliters. Ans. indd 38 You cannot change a mass to a volume (unless you have a value for density). 81 39 What is the volume of 125 g of water? Ans. 00 ggրրmL. 98 mL Ans. 83 Ans. 1 g of sugar per 100 mL of solution. What mass of solution will contain 182 g of sugar? What mass of water is required to make this solution? Ans. 2 gրcm3. 1-cm3 piece of jewelry? 103 g) Ans. 8 gրcm3. 00 mm2. 7 g? 3 Ans. 87 How much had the chain of the prior problem cost if the gold alloy had cost $1400ր 0րTroy ounce when it was purchased?
The only other reason a zero would be present is if it were significant. 0000 ϫ 103 cm ϩ 2 ϫ 10Ϫ2 cm Ans. 0 cm The fraction added is so small relative to the first number that it does not make any difference within the number of significant figures allowed. (b) This part is exactly the same as part (a). The same numbers, expressed in scientific notation with the same number of significant digits, are used. Be aware that when a small number is added to a much larger one, the small number may not affect the value of the larger within the precision of its measurement.
38 Change 171 K and 422 K to degrees Celsius. 171 K Ϫ 273Њ ϭ 102ЊC Ans. 422 K Ϫ 273 73Њ ϭ 1499ЊC Note that a change in temperature in kelvins is the same as the equivalent change in temperature in degrees Celsius. 39 Convert 0°C and 30°C to kelvins. Calculate the change in temperature from 0°C to 30°C on both temperature scales. 0ЊC ϩ 273 73Њ ϭ 273 K 30ЊC ϩ 273Њ ϭ 303 K Ans. 0 miրh. ր (b) Which of these—the reciprocal or the original factor label—is multiplied to change miles to hours? Ans. 00 dollarsրpound.